ID: A 1 G.CO.C.11: Special Quadrilaterals 2 Answer Section 1 ANS: 3 REF: 010404a 2 ANS: 3 REF: 081913geo 3 ANS: 2 REF: 081501geo 4 ANS: 1 REF: 011716geo Engineering Triangle ABD in the diagram has a right angle A and sides AD = 4.9cm and AB = 7.0cm. 3 and 4 right angles 5. Abcd is a parrallelogram p,q are the mid points of sides about and dc respectively. To find : ∠BCD : ∠ABE Solution : We have A is the centre of the ci… - 1427736 Show that (i) ABCD is a square (ii) diagonal BD bisects ∠B as well as ∠D. Given:{eq}\angle BAC \text{ is congruent to } \angle ACD, {/eq} segment BD bisects segment AC, and segment AC bisects {eq}\angle BCD {/eq}. Dazu gehört der Widerspruch gegen die Verarbeitung Ihrer Daten durch Partner für deren berechtigte Interessen. star. sides of square ABCD∠OAD = ∠OCB| ∵    AD || BC and transversal AC intersects them∠ODA = ∠OBC| ∵    AD || BC and transversal BD intersects them∴ ∆OAD ≅ ∆OCB| ASA Congruence Rule∴ OA = OC    ...(1)Similarly, we can prove thatOB = OD    ...(2)In view of (1) and (2),AC and BD bisect each other.Again, in ∆OBA and ∆ODA,OB = OD | From (2) aboveBA = DA| Opp. Prove that if a diagonal of a parallelogram bisects one angle of the parallelogram, then the parallelogram is a rhombus. Here in our parallelogram side AB is parallel to side CD. prove:AC bisects angle BAD and angel BCD. To Prove: Quadrilateral ABCD is a square. Each answer of the exercise has been carefully compiled and developed keeping in consideration the latest CBSE syllabus. Analyze the diagram below and complete the instructions that follow. Transcript. Get detailed answer of 6. AC and BD bisect each other. Solution: Given, Three angles are 110°, 50° and 40° Prove that if the diagonals of a parallelogram are congruent, then the parallelogram is a … Related Questions. It is given that AB = AD and BC = DC. Show that if the diagonals of a quadrilateral are equal and bisect each other at right angles, then it is a square. given 2. Advertisement Remove all ads. (ii) diagonal BD bisects ∠B as well as ∠D.Proof: (i) ∵ AB || DCand transversal AC intersects them.∴ ∠ACD = ∠CAB    | Alt. Prove that AB = AD and CB = CD . 50P and 4CP. AEB bisects CED AC CED & BD CED 2. D x C. See Answer. so same rule is applied here.i.e

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